Smithfield Family Flyaway Sweepstakes – Win a $3,500 travel gift card!

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Win a $3,500 travel gift card!

ENTER SWEEPSTAKES HERE – Smithfield Sweepstakes page.
You will need to be a member of Smithfield’s Friends and Family Program (it’s FREE to join).

ENTRY LIMIT – you may obtain one entry into the drawings each week you visit the website per the schedule below. There is a maximum of obtaining eight (8) entries total into Grand Prize and First Place Prize drawings.

ELIGIBILITY – Smithfield Family Flyaway Sweepstakes (the “Sweepstakes”) is open only to participants of the Smithfield Friends & Family Program (the “Program”) who are legal residents of the fifty (50) United States and the District of Columbia and who are at least eighteen (18) years old at the time of entry (19+ in Alabama and Nebraska).

SWEEPSTAKES ENTRY PERIOD – The Sweepstakes begins on or around January 14, 2019 at 12:00 a.m. Eastern Time (“ET”) and ends on or about March 10, 2019 11:59 p.m. ET.

PRIZES – ONE (1) GRAND PRIZE: The Grand Prize Winner will receive a travel gift card of choice valued at $3,500 from one of the following: Delta Vacations, Southwest Vacations® or United Vacations®. Approximate Retail Value (“ARV”): $3,500.

FOUR (4) FIRST PLACE PRIZES: Each First Place Prize Winner will receive a gift card valued at $500 from Hotels.com®. Gift Card will be delivered electronically, or via USPS or expedited service delivery at Sponsor’s discretion.

TOTAL ARV OF ALL PRIZES: $5,500
WINNER’S LIST – For a winner list, please send a self-addressed and stamped to: “Smithfield Family Flyaway Sweepstakes, Winner List” c/o Doner CX, 8050 Rowan Road, Suite 200, Cranberry Twp., PA 16066. The winner list will be available and distributed after winner confirmation is complete. Request must be received within 30 days of the end of the Promotion Period.

RULES – See sweepstakes rules here (embedded).

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